If #f(x)=x^2-3# and #g(x)=5x#, how do you find f(g(-3))?

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Answer 1 · 2018-07-28T13:17:25

222

first, find #f(g(x))#

#f(g(x))=(5x)^2-3#

#f(g(x))=25x^2-3#

now, put #x=-3#

# f(g(-3))=25*9-3#

#f(g(-3))=222#

Answer 2 · 2018-07-28T13:18:02

#f(g(-3))=222#

#"begin by evaluating "g(-3)#

#g(-3)=5xx-3=-15#

#"now evaluate "f(g(-3))tof(-15)#

#f(-15)=(-15)^2-3=225-3=222#