If #f(x) = x^2 + 3x# and #g(x) = 4x - 1#, what is #(f@g)(0)#?
1 Answer
Mar 4, 2018
Explanation:
#"substitute "g(x)=4x-1" into "f(x)#
#rArrf(4x-1)#
#=(4x-1)^2+3(4x-1)#
#=16x^2-8x+1+12x-3#
#=16x^2+4x-2#
#rArr(f@g)(x)=16x^2+4x-2#
#"to evaluate "(f@g)(0)" substitute x = 0 into "(f@g)(x)#
#rArr(f@g)(0)=0+0-2=-2#
