Question

If `h(x)=f(x)g(x)` and `f(x)=2x+5`, how do you determine g(x) given `h(x)=6x+15`?

Answer 1

`g(x)=3` if `x!=-5/2`

Explanation:

`g(x)=(h(x))/f(x)`

then

`g(x)=(6x+15)/(2x+5)=(3(2x+5))/(2x+5)`

`g(x)=3` if `2x+5!=0->x!=-5/2`