If I have 45 liters of helium in a balloon at 25 degress celcius and increase the tempurate to 55 degrees celcius what will the new volume be?

1 Answer
May 13, 2017

Answer:

#50.L#

Explanation:

This is a problem involving the temperature-volume relationship of gases, which is represented by Charles's law:

#(V_1)/(T_1) = (V_2)/(T_2)#

Remember that #T# is the absolute temperature, so you must convert the temperature from Celcius to Kelvin:

#25 ^o C + 273 = 298K#
#55 ^o C + 273 = 328 K#

Now, rearrange the equation to solve for #V_2# (the new volume):

#V_2 = (V_1)(T_2)/(T_1)#

and plug in the known values:

#V_2 = 45 L(328 K)/(298 K) = 50.L#

(The decimal place is present to emphasize there are two significant figures, otherwise it's arbitrary whether you're using one or two.)