# If I start with 5 grams of C_3H_8, what is the theoretical yield of water in the equation C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O?

Mar 11, 2016

$\approx 8.18 g m$
the molar mass of${C}_{3} {H}_{8} = 3 \times 12 + 8 \times 1 = 44 g m m o {l}^{=} 1$
molar mass of water=$18 g m m o {l}^{-} 1$
As per the equation 44 gm${C}_{3} {H}_{8}$ gives $4 \times 18 = 72 g m$ water
1gm ${C}_{3} {H}_{8}$ gives $4 \times 18 = \frac{72}{44} g m$ water
5gm ${C}_{3} {H}_{8}$ gives $4 \times 18 = \frac{72}{44} \times 5 \approx 8.18 g m$ water