If $ln x - ln (1/x) = 2$ , then how do you find $x$ ?

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Answer 1 · 2016-10-25T17:49:03

$x = e$

We use the rule $lna - lnb = ln(a/b)$ to start the solving process.

$ln(x/(1/x)) = 2$

$ln(x^2) = 2$

If $lna = b$ , $e^b= a$

$x^2 = e^2$

$x = +-sqrt(e^2)$

$x = +-e$

However, the negative answer is not possible as it renders the original equation undefined.

Hopefully this helps!

If ln x - ln (1/x) = 2ln x - ln (1/x) = 2, then how do you find xx?