If #log_2(x^2-1) = log_2 8#, what is the solution set for #x#?
1 Answer
Jan 9, 2018
Explanation:
Since the logarithms are on equal bases, they can be cancelled immediately.
#x^2 - 1 = 8#
#x^2 = 9#
#x = +- 3#
Both solutions are valid because they satisfy the original equation.
Hopefully this helps!
