If #log_2(x^2-1) = log_2 8#, what is the solution set for #x#?

1 Answer
Jan 9, 2018

#x = +- 3#

Explanation:

Since the logarithms are on equal bases, they can be cancelled immediately.

#x^2 - 1 = 8#

#x^2 = 9#

#x = +- 3#

Both solutions are valid because they satisfy the original equation.

Hopefully this helps!