If one mole of carbon-12 ("^12C) atoms was weighed, what would it have a mass of?

Feb 1, 2017

Answer:

Well, approx. $12 \cdot g$.

Explanation:

By definition, $\text{Avogadro's number}$ $=$ $6.022 \times {10}^{23} \cdot m o {l}^{-} 1$ is the number of ""^12C $\text{atoms}$ present in a $12 \cdot g$ sample of ""^12C.

See this older answer and links.