Question

If pressure on a gas is increased from 2atm to 4atm than its volume decreases from 1, 6Lto 4L 2, 8L to2L 3, 3Lto1L 4, 4L to 2L?

Answer 1

Well old Boyle's Law holds that at constant temperature, and a given quantity of gase, `P_1V_1=P_2V_2`

Explanation:

And so we solve for `V_2`

`=(P_1V_1)/P_2=(2*atmxxV_1)/(4*atm)`, i.e. `1/2V_1`....HALF THE ORIGINAL VOLUME...

And the only option that qualifies is `4.`...i.e. the VOLUME contracts from `4*L` to `2*L`...