If sin(t)=0.8 and cos(t)=0.6. what is sin(t)+cos(-t)+sin(-t+2pi)?

Question

3081 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-02T05:57:50

0.6

From given data,

$sin t = 0.8$ $sint=0.8$ & $cos t = 0.6$ $cos t=0.6$

Let $x = sin t + cos (- t) + sin (2 π - t)$ $x=sint+cos(-t)+sin(2pi-t)$

[ $cos (- t) = cos t & sin (2 π - t) = - sin t$ $cos(-t)=cost & sin(2pi-t)=-sint$ ]

$:.x=sint+cost-sint$

$=>x=cancelsint+cost-cancelsint$

$=>x=cost$

$:.x=0.6$