Question

If sin(t)=0.8 and cos(t)=0.6, what is `sin(t)+cos(-t)+sin(-t+2pi)`?

Answer 1

`0.6`

Explanation:

Given that

`\sin t=0.8` & `\cos t=0.6`

`\therefore \sin t+\cos(-t)+\sin(-t+2\pi)`

`= \sin t+\cost+\sin(2\pi-t)`

`= \sin t+\cost-\sin t`

`=\cost`

`=0.6`