If #sin theta = 1/4, then cos(90degrees - theta) =?

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Explanation please?

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Answer 1 · 2018-01-29T12:52:45

$cos(90^@-theta)=1/4$

For all angles $A$ , $cos(90^@-A)=sinA$

Hence $cos(90^@-theta)=sintheta=1/4$

Answer 2 · 2018-01-29T13:44:26

$1/4$

$"using the "color(blue)"trigonometric identity"$

$•color(white)(x)cos(90-theta)^@=sintheta$

$rArrcos(90-theta)=sintheta=1/4$