# If sin x = 0.6, what is the value of cos x?

${\sin}^{2} \left(x\right) + {\cos}^{2} \left(x\right) = 1$
If $\sin \left(x\right) = 0.6$
${\left(0.6\right)}^{2} + {\cos}^{2} \left(x\right) = 1$
${\cos}^{2} \left(x\right) = 1 - 0.36 = 0.64$
$\cos \left(x\right) = \pm 0.8$