If sin x = 0.6, what is the value of cos x? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Alan P. Apr 15, 2015 sin^2(x)+cos^2(x) = 1sin2(x)+cos2(x)=1 If sin(x) = 0.6sin(x)=0.6 then (0.6)^2+cos^2(x) = 1(0.6)2+cos2(x)=1 cos^2(x) = 1 - 0.36 = 0.64cos2(x)=1−0.36=0.64 cos(x) = +- 0.8cos(x)=±0.8 Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If sec theta = 4secθ=4, how do you use the reciprocal identity to find cos thetacosθ? How do you find the domain and range of sine, cosine, and tangent? What quadrant does cot 325^@cot325∘ lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that 1+tan^2 theta = sec ^2 theta1+tan2θ=sec2θ? See all questions in Relating Trigonometric Functions Impact of this question 94330 views around the world You can reuse this answer Creative Commons License