If sin x = 0.6, what is the value of cos x? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Alan P. Apr 15, 2015 #sin^2(x)+cos^2(x) = 1# If #sin(x) = 0.6# then #(0.6)^2+cos^2(x) = 1# #cos^2(x) = 1 - 0.36 = 0.64# #cos(x) = +- 0.8# Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 92816 views around the world You can reuse this answer Creative Commons License