If #sin x= 4/5#, how do you find cos x?

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Mar 1, 2018

cosx= #3/5#

Use Trignometrical identity cosx = #sqrt(1-sin^2 x)#

cos x = #sqrt(1 -16/25)# =#sqrt(9/25)# = #3/5# to be the value in the first quadranr.

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