If $tan x = \frac{2}{7}$ $tan x= 2/7$ , how do you find sec x and x lies in the 3rd quadrant so both are negative?

Question

4494 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-17T00:14:07

See graph below:
enter image source here

$sec (x) = \frac{1}{cos (x)} = - \frac{\sqrt{53}}{2}$ $sec(x) = 1/(cos(x)) = -sqrt(53)/2$

If tanx=27tan x= 2/7, how do you find sec x and x lies in the 3rd quadrant so both are negative?