If the actual yield of #PBr_3# s found to be 22.3 g, how do you find the percent yield in this reaction?

The reaction between phosphorus and liquid bromine is outlined as: #2P(s) + 3Br_2(l) -> 2PBr_3(l)#

1 Answer
Dec 3, 2016

Answer:

You cannot assess the percentage yield in this reaction.

Explanation:

#P+3/2Br_2 rarr PBr_3#

You have reported a mass of #"phosphorus bromide"# that is recovered. There are no data with respect to the amount of bromine or phosphorus used to synthesize the tribromide.

#"Moles of"# #PBr_3=(22.3*g)/(270.69*g*mol^-1)=??mol#.

So, you know the minimum quantities of bromine and phosphorus used in the synthesis reaction. You do not know the actual quantities utilized.