If the frequency of the #p# allele is .63 in the population then what is the frequency of the #q# allele?

1 Answer
Jun 3, 2018

Answer:

#0.37#

Explanation:

We use the Hardy-Weinberg equation, which states that,

#p^2+2pq+q^2=1#

where:

  • #p^2 #is the frequency of the homozygous genotype #"AA"#

  • #2pq# is the frequency of the heterozygous genotype #"Aa"#

  • #q^2# is the frequency of the homozygous genotype #"aa"#

  • #p# is the frequency of the dominant allele #"A"#

  • #q# is the frequency of the recessive allele #"a"#

Since we only need to find the frequency of the #q# allele, we can factor the equation into:

#(p+q)^2=1#

Plugging in for #p=0.63#, we get:

#(0.63+q)^2=1#

#0.63+q=1#

#q=1-0.63#

#=0.37#