# When 2 heterozygotes were crossed with each other i.e. #AaBb# x #AaBb#, the progeny showed: (i) A_B_ = 400 (ii) A_bb = 310 (iii) aaB_ = 290 (iv) aabb = 200 Does this prove Mendelian ratio? Find with a chi square test. (A and B- dominant)

##### 1 Answer

The results of the dihybrid cross in question do not indicate Mendel's law of independent assortment.

#### Explanation:

The Mendelian ratio of a dihybrid cross is expected to create

To determine the expected numbers of genotypes in the progeny of the cross in question, multiply the number of each genotype times its expected ratio out of

The Chi-square

**Genotype: #"A-B-"#**

Observed:

Expected:

**Genotype: #"A-bb"#**

Observed:

Expected:

**Genotype: #"aaB-"#**

Observed:

Expected:

**Genotype: #"aabb"#**

Observed:

Expected:

**Determine the Chi-Square Sum**

Once you have the Chi-Square sum, you need to use the Probability table below to determine the probability that the results of the dihybrid cross is due to the Mendelian inheritance of independent assortment.

The degree of freedom is the number of categories in the problem minus 1. In this problem there are four categories, so the degree of freedom is 3.

Follow Row

The sum of