# If the Hubble Space Telescope proved that Hubble's constant is actually half as large as it is currently believed to be, what would the implied age of the universe be in comparison to the current accepted value?

In appropriate units of time and distance, the reciprocal $\frac{1}{H} _ o$ of Hubble constant ${H}_{o}$ gives the age of our universe. As the reciprocal of ${H}_{o} / 2 = \frac{2}{H} _ o$, the age is doubled.
The dimension of Hubble constant, $\left[{H}_{o}\right] - L {L}^{- 1} {T}^{- 1} = {T}^{- 1}$. The dimension of thr reciprocal $\left[\frac{1}{H} _ o\right] = T$
As of now, different estimates of ${H}_{o}$ have a range around 70 km/s/mega parsec.