If the length of a #17 cm# spring increases to #61 cm# when a #4 kg# weight is hanging from it, what is the spring's constant?

1 Answer

Answer:

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See Below.

Explanation:

We know,

The linear expansion of a elastic body is directly proportional to the force exerted on it.

So, #F prop -Deltax#. [The minus is to show that the body is trying to regain its original shape.]

So, #F= -kDeltax# [#k# is the constant of proportionality and #k != 0#]

Now, Subsititute The Values in the relation.

#color(white)(xx)F = -kDeltax#

#rArr mg = -k(61 - 17)# [Here, #F = mg#]

#rArr 4 xx 10 = -kxx44# [Taking #g = 10# #m/s^2#]

#rArr k = -(cancel4 xx 10)/cancel44_11#

#rArr k = -10/11#

Hence Explained.