# If the length of a 17 cm spring increases to 63 cm when a 3 kg weight is hanging from it, what is the spring's constant?

Mar 4, 2017

The spring constant is $= 63.9 N {m}^{-} 1$

#### Explanation:

We apply this formula

$F = 3 \cdot g = 3 \cdot 9.8 = 29.4 N$

$x = 0.63 - 0.17 = 0.46 m$

The spring constant is

$k = \frac{F}{x} = \frac{29.4}{0.46} = 63.9 N {m}^{-} 1$