Question

If the length of a `17 cm` spring increases to `63 cm` when a `3 kg` weight is hanging from it, what is the spring's constant?

Answer 1

The spring constant is `=63.9Nm^-1`

Explanation:

We apply this formula

`F=3*g=3*9.8=29.4N`

`x=0.63-0.17=0.46m`

The spring constant is

`k=F/x=29.4/0.46=63.9Nm^-1`