If the length of a #19 cm# spring increases to #54 cm# when a #4 kg# weight is hanging from it, what is the spring's constant?

1 Answer
Oct 27, 2017

Answer:

The spring constant is 112 N/m.

Explanation:

Spring constant it typically given in units of N/m, so I will convert the spring lengths to m. 19 cm = 0.19 m & 54 cm = 0.54 m

The weight of that 4 kg mass is #m*g = 4 kg*9.8 m/s^2 = 39.2 N#.
The amount of stretch that the weight caused was
#0.54 m - 0.19 m = 0.35 m#

Therefore the spring constant is #(39.2 N)/(0.35 m) = 112 N/m#

I hope this helps,
Steve