If the length of a #26 cm# spring increases to #43 cm# when a #4 kg# weight is hanging from it, what is the spring's constant?

1 Answer
Jun 23, 2016

Answer:

#k = 230.82kg/m#

Explanation:

Hooke's Law states that the spring constant #(k)# and displacement of the spring are related to the Force applied on the spring by the equation #F =-kx#

The Force is determined by the mass times gravity.

#m = 4kg#
#g = 9.81 m/s^2#

#F = (4kg)(9.81m/s^2)#

#F = 39.24 N#

#k =?#
#x = -43cm+26cm = 17cm = -0.17m#

#39.24 N = -k(-0.17 m)#

#(39.24N)/(-0.17m) = -k#

#-230.82 = -k#

#k = 230.82kg/m#