Question

If the length of a `29 cm` spring increases to `47 cm` when a `15 kg` weight is hanging from it, what is the spring's constant?

Answer 1

`=833.33Nm^-1`

Explanation:

`F=kx`
force `F=mg=15xx10N=150N`
`g =10 ms^-2`
Increase in length `l=(47-29)cm=18cm=0.18m`
force constant `k=F/x=150/0.18N/m=833.33Nm^-1`