If the length of a #35 cm# spring increases to #73 cm# when a #3 kg# weight is hanging from it, what is the spring's constant?

1 Answer
Dec 13, 2015

Answer:

The spring constant will be #-3 N/m#

Explanation:

Given Data:

#Displacement (x) = 73 cm - 35 cm = 38 cm#
#= 38 * 10^-3 m#
#x= 0.38 m#

We've just done this to get it into the SI units or MKS system.

Force (F) #= m*a = 3 * 0.38#
#F = 1.14 N#

Spring Constant (k) = ?

We know:

Spring Constant (k) #= - F/x #

#k = -1.14/0.38#

#k = -3#

This is our final answer.

The trick here and most of these types of questions, the answer will be the mass we multiplying in the force.