If the length of a rectangle is represented by $(5x-3)$ and the width is represented by $(2x)$ , what is the area of the rectangle in terms of $x$ ? Please show working.

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Answer 1 · 2015-12-26T19:42:21

For this problem, you ought to remember the formula for area of a rectangle is (length • width)

Let A be area, l be length and w be width.

A = (5x - 3)(2x)
Use the distributive property --> $10x^2$ - 6x

The rectangle has an area of $10x^2$ - 6x

Answer 2 · 2015-12-26T19:47:21

Area: $10x^2-6x$

Area of rectangle $= color(red)("length") xx color(blue)("width")$

Area of given triangle $=color(red)((5x-3))xxcolor(blue)((2x))$

$color(white)("XXXXXXXXXXX")=(color(red)((5x))xxcolor(blue)((2x)))-(color(red)((3))xxcolor(blue)((2x)))$

$color(white)("XXXXXXXXXXX")=10x^2-6x$

If the length of a rectangle is represented by (5x-3)(5x-3) and the width is represented by (2x)(2x), what is the area of the rectangle in terms of xx? Please show working.