# If the magnitude of v is 10, and the direction vector is 60°, what is the x component of v?

Nov 15, 2015

$x = 5$.

#### Explanation:

I'll suppose the direction of the vector is 60º above the horizontal. So, we have:
$v = 10$,
alpha = 60º.
To find the $x$-component, we simply multiply $v$ times the cosine of $\alpha$. So,
$x = v \cdot \cos \left(\alpha\right)$,
x = 10 * cos(60º),
$x = 10 \cdot \frac{1}{2}$,
$x = 5$.

Hope it Helps! :D .