If the pH is 14.75, what is #[OH^-]#?

1 Answer
Jun 15, 2016

Answer:

In aqueous solution under standard conditions, #pH+pOH=14#

Explanation:

Given the above, #pOH# #=# #-0.75#.

Thus #[HO^-]# #=# #10^(-(-0.75))# #=# #10^(+0.75)# #=# #5.62*mol*L^-1#.