If w is a complex cube roots of unity then w^17: 1. 0 2. 1 3. w 4. w^2 Pleas explain? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Ratnaker Mehta Apr 16, 2017 omega in CC is a cube-root of unity :. omega^3=1. :. omega^17=omega^(15+2)=omega^15*omega^2=((omega^3)^5)*omega^2=((1)^5)*omega^2=omega^2. :." Answer : Option 4. "omega^2. Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of 10+6i? How do I find the complex conjugate of 14+12i? What is the complex conjugate for the number 7-3i? What is the complex conjugate of 3i+4? What is the complex conjugate of a-bi? See all questions in Complex Conjugate Zeros Impact of this question 2094 views around the world You can reuse this answer Creative Commons License