If x-2 is a factor of #5x^2+bx+4# what is the value of b?

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Answer 1 · 2018-05-02T16:08:14

#b = - 12#

Given;

#5x^2 + bx + 4#

Factor: #x - 2#

Since its a factor therefore;

#x - 2 = 0#

#x = 2#

Substitute the value of #x# into the main equation..

#5(2)^2 + b(2) + 4 = 0#

#5(4) + 2b + 4 = 0#

#20 + 2b + 4 = 0#

#24 + 2b = 0#

#2b = - 24#

#b = -24/2#

#b = -12#