Question

If `x-2` is a factor of `x^2-bx+b` where `b` is constant, what is the value of `b`?

Answer 1

`b=4`

Explanation:

If `(x-2)` is a factor of `x^2-bx+b`, `2` is a zero of `x^2-bx+b` and hence putting `x=2` in `x^2-bx+b`, we should get `0`.

Hence `2^2-2b+b=0` or

`4-b=0` i.e. `b=4`.