If #y 12x- 7# were changed to #y=12x+ 1#, how would the graph of the new function compare with the original?

1 Answer
Apr 22, 2017

The new function would be shifted vertically up by 8.

Explanation:

Given: #f(x) = 12x - 7 " and " g(x) = 12x + 1#

Both functions are in the form #y = mx + b#, where #m = #slope and #b# is the #y#-intercept #(0, b)#

Both functions have the same slope, #m = 12#. This means they are parallel.

The first function has a #y#-intercept #(0, -7)# and the second function has a #y#-intercept #(0, 1)#. This is a positive difference of #8#.

This means the new function would be shifted vertically up by #8# from the first function.