# If you are studying a population a 92% exhibits the dominant phenotype, what percentage exhibits the recessive phenotype?

Jun 27, 2018

8%

#### Explanation:

Hardy-Weinberg equation states that:

${p}^{2} + 2 p q + {q}^{2} = 1$

Factoring, we get:

${\left(p + q\right)}^{2} = 1$

Letting $p$ be the dominant phenotype, we get p=92%=0.92.

$\therefore {\left(0.92 + q\right)}^{2} = 1$

$0.92 + q = 1$

$q = 0.08$

=8%