# If you have 21 moles of gas held at a pressure of 78 ATM and a temperature of 900 k, what is the volume of the gas?

Jun 27, 2014

In this questions certain $a r e g i v e n ,$ of moles ,n = 21 mol, Pressure P = 78 atm, Temperature T = 900 K, Volume V = ?

We have to calculate the volume of the given moles of gas at specific temperature and pressure.

Using Ideal Gas equation;

PV = nRT

V = nRT /P ( R = gas constant = 0.08206 L atm $m o {l}^{-} 1$${K}^{-} 1$ )

V= 21 mol x 0.08206 L atm $m o {l}^{-} 1$${K}^{-} 1$ x 900K / 78 atm

V= 73.854 L atm / 78 atm = 0.946 L