If you have 381 g Cu and 1359 g AgNO3, how many grams of silver could be made?
You could make 863.0 g of silver.
Start by writing the balanced chemical equation for this single replacement reaction
Anytthing less than that, and silver chloride will act as a limiting reagent.
Use the molar masses of copper and of silver nitrate to determine how many moles of each you have
Notice that you have insufficient silver nitrate to allow for all of the moles of copper to react. That much copper would have needed
As a result, all of the silver nitrate will react, and you'll be left with excess copper metal.
Notice that you have a
As a result, you'll get
Now use silver's molar mass to determine how many grams you'd produce
Rounded to four sig figs, the number of sig figs given for the mass of silver nitrate, the answer will be
Now we have 281g Cu = 381/63.5 = 6 mol.
We have 1359g silver nitrate = 1359/170 = 8 mol
But 6 mol Cu requires 12 mol silver nitrate.
So it is the 8 mol of silver nitrate which will decide the yield of the reaction since Cu is in XS.
So 8 mol silver nitrate
8 mol Ag = 108 x 8 = 864g