If you have 4 moles each of #CO# and #O_2#, which is the limiting reagent and why?

1 Answer
Jan 11, 2017

Answer:

We need a stoichiometrically balanced oxidation reaction..........

Explanation:

#CO(g) +1/2O_2(g) rarr CO_2(g)#

Given the equation, if there are equimolar carbon monoxide and dioxygen, dioxygen is the reagent in excess, and carbon monoxide is the limiting reagent.