# If you start with 60 CaCO_3's, how many CaO's will you get?

Sep 10, 2016

#### Explanation:

Calcium caronate is known to decompose under (fierce) heating to give calcium oxide and carbon dioxide.

To represent this decomposition we write the stoichiometrically balanced equation:

$C a C {O}_{3} \left(s\right) + \Delta \rightarrow C a O \left(s\right) + C {O}_{2} \left(g\right) \uparrow$

So if I start with $1$ $m o l$ of calcium carbonate, $100.09 \cdot g$, at most I can get $56.08 \cdot g$ calcium oxide, for these masses are the molar equivalents. The difference in masses, some $44 \cdot g$, represents the molar equivalent mass of evolved carbon dioxide. The masses MUST be conserved, because masses are conserved in every chemical reaction.

Here I started with 60 formula units of calcium carbonate; at most I can get 60 formula units of calcium oxide. How many formula units of carbon dioxide gas were evolved in this scenario? If you are not satisfied with this answer, voice your objection, and I will give it another go.