# If your body takes in 20 moles of O_2 from the air, and you eat 45 moles of sugar, which is the limiting reactant?

Mar 16, 2016

#### Answer:

${C}_{6} {H}_{12} {O}_{6} + 6 {O}_{2} \rightarrow 6 C {O}_{2} + 6 {H}_{2} O + \text{heat}$

Clearly, oxygen is the limiting reagent.

#### Explanation:

I have simplified glucose metabolism with a simple combustion reaction. The balanced combustion equation clearly indicates that each mole of sugar, ${C}_{6} {H}_{12} {O}_{6}$, requires $6$ mol of dioxygen gas for combustion.

Needless to say, this scenario is a bit unrealistic. Who would eat over 8 kilograms of sugar in one sitting?