If z=x+iy and |z-1|^2+|z+1|^2=4, determine the position of the points z in the complex plane?

#|z-1|^2+|z+1|^2=4#

1 Answer
Dec 30, 2017

Please see below.

Explanation:

As #z=x+iy# we can write #|z-1|^2+|z+1|^2=4# as

#|x-1+iy|^2+|x+1+iy|^2=4#

or #(x-1)^2+y^2+(x-1)^2+y^2=4#

or #2x^2+2+y^2=4#

or #2x^2+y^2=2#

or #x^2/1+y^2/2=1#

Hence,the position of the points #z# in the complex plane is given by the ellipse #x^2/1+y^2/2=1#, which is displayed below.

graph{x^2/1+y^2/2=1 [-4, 4, -2, 2]}