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Answer 1 · 2017-05-18T20:40:03

If you want to determine what metal you have, and you know it is a pure metal, it can be identified simply by knowing its specific heat capacity $C_{P}$ $C_P$ in ${J/g}^{\circ} C$ $"J/g"^@ "C"$ , i.e. how much heat it takes to raise $1 g$ $"1 g"$ of the substance temperature by $1^{\circ} C$ $1^@ "C"$ .

Heat flow $q$ $q$ is the amount of heat content in $J$ $"J"$ flowing through a substance, which causes it to change in temperature. Knowing $q$ $q$ and the change in temperature, $DeltaT$ , as well as the mass of the substance in $"g"$ , the heat capacity can be determined:

$q = mC_PDeltaT$

We were given:

$m = "15.0 g"$
$C_P = ???$
$DeltaT = T_f - T_i = 18.8^@ "C" - 17.7^@ "C"$
$q = "6.35 J"$

Therefore:

$C_P = q/(mDeltaT)$

$= ("6.35 J")/("15.0 g" xx (18.8^@ "C" - 17.7^@ "C"))$

$= color(blue)("0.385 J/g"^@ "C" -= C_(P("Cu")))$

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