# In a 0.70 M solution of benzoic acid, what percentage of the molecules are ionized (CHEMISTRY 1B problem)?

## Benzoic acid is a weak acid that has antimicrobial properties. Its sodium salt, sodium benzoate, is a preservative found in foods, medications, and personal hygiene products. Benzoic acid dissociates in water: C_6H_5COOH⇌C_6H_5COO^−+H^+ The $p K a$ of this reaction is $4.2$. In a $0.70 M$ solution of benzoic acid, what percentage of the molecules are ionized? Express the percentage numerically using two significant figures. Work It's incomplete, but I fulfilled the formula, and got (below)... Answer result

Mar 14, 2017

$p H = 10.23$
$8.5 \setminus \times {10}^{- 2}$ M NaOCl
${K}_{a} \left(H C l O\right) = 2.9 \setminus \times {10}^{- 8}$
${K}_{b} \left(C l {O}^{-}\right) = \frac{1.0 \setminus \times {10}^{- 14}}{2.9 \setminus \times {10}^{- 8}}$