# In a right triangle ABC with angle A equal to 90o, find angle B and C so that sin(B) = cos(B). ?

Jun 2, 2018

B and C measures ${90}^{\circ}$

#### Explanation:

Let,
b be the length of the side opposite of the angle B
c the length of the side opposite of the angle C
h the length of the hypotenuse.

sin(B) = $\frac{b}{h}$ and cos(B) =$\frac{c}{h}$

sin(B) = cos(B) means $\frac{b}{h} = \frac{c}{h}$

By cross multiplication,

$b = c$

This gives that the triangle is isosceles so,

B and C angle is equal to ${45}^{\circ}$