Question

In a titration experiment, 12.5 mL of 0.500 M `H_2SO_4` neutralizes 50.0 mL of `NaOH`. What is the concentration of the `NaOH` solution?

Answer 1

0.25 M

Explanation:

`0.500 (mol)/L H_2SO_4 * 0.0125 L = 0.00625 mol H_2SO_4`

Write a balanced equation for the reaction:

`H_2SO_4 + 2NaOH -> 2H_2O + Na_2SO_4`

1 mol `H_2SO4` neutralizes 2 mol `NaOH`, so:

`0.00625*2 = 0.0125 mol NaOH`

`0.0125 mol NaOH / 0.05 L= 0.25 M NaOH`