In carbohydrates, if there is more than 1 asymmetrical carbon atom, how do we determine the D and L-forms?

1 Answer
Jul 22, 2015

You look at the stereochemistry of the highest-numbered chiral centre in a Fischer projection.

Explanation:

If the #"OH"# in the highest-numbered chiral carbon (closest to the bottom) is on the right, we have a D-sugar.

If the #"OH"# is on the left, we have an L-sugar.

For example, the Fischer projection of D-glucose is

www.chem.wisc.edu
(from www.chem.wisc.edu)

This is a D-sugar because the #"OH"# on #"C-5"# is on the right.

Do not be fooled into thinking that to get the structure of L-glucose, you just invert the configuration at #"C-5"# to get

metabolomics.jp
(from metabolomics.jp)

This is an L-sugar, but it is L-idose.

To get the structure of L-glucose, you must invert the configuration of every chiral centre.

DLGlucose
(from www.easyochem.com)

D-Glucose and L-glucose are enantiomers — nonsuperimposable mirror images of each other.