# In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o. 6CO(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g) How many grams of glucose are produced from 21.0g of CO2?

## How to set problem, I believe I'm going from grams to grams

$6 C {O}_{2} \left(g\right) + 6 {H}_{2} O \left(l\right) + \Delta \rightarrow {C}_{6} {H}_{12} {O}_{6} \left(a q\right) + 6 {O}_{2} \left(g\right)$
$6 C {O}_{2} \left(g\right) + 6 {H}_{2} O \left(l\right) + \Delta \rightarrow {C}_{6} {H}_{12} {O}_{6} \left(a q\right) + 6 {O}_{2} \left(g\right)$
$\text{Moles of } C {O}_{2} \left(g\right)$ $=$ $\frac{21.0 \cdot g}{44.0 \cdot g \cdot m o {l}^{-} 1}$ $=$ $0.477$ $m o l$
$180.16 \cdot g \cdot m o {l}^{-} 1 \times \frac{1}{6} \times 0.477 \cdot m o l$ $=$ ?? $g$