In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o. 6CO(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g) How many grams of glucose are produced from 21.0g of CO2?

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How to set problem, I believe I'm going from grams to grams

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Answer 1 · 2016-03-26T21:28:27

#6CO_2(g) + 6H_2O(l) + Delta rarr C_6H_12O_6(aq) + 6O_2(g)#

#6CO_2(g) + 6H_2O(l) + Delta rarr C_6H_12O_6(aq) + 6O_2(g)#

#"Moles of "CO_2(g)# #=# #(21.0*g)/(44.0*g*mol^-1)# #=# #0.477# #mol#

#180.16*g*mol^-1xx1/6xx0.477*mol# #=# #??# #g#