# In the equation 2KClO_3 -> 2KCI + 3O_2, how many moles of oxygen are produced when 5.05 m of KClO_3 decompose completely?

##### 1 Answer
Nov 18, 2016

7.58 moles of ${O}_{2}$ are produced.

#### Explanation:

There are multiple lines of reasoning for solving this. Let me give you the most detailed:

You start with a plan: we will convert moles of $K C l {O}_{3}$ to moles of ${O}_{2}$ using the balanced chemical equation:

You will get 3 moles of ${O}_{2}$ for every 2 moles of $K C l {O}_{3}$ you decompose.

Now let's substitute the number of moles of $K C l {O}_{3}$ that you actually started with:

$5.05 \text{ moles "KClO_3 xx (3 " moles " O_2)/(2 " moles " KClO_3) = 7.575 " moles } {O}_{2}$

Finally, since we started with three significant figures, we have to end up with three significant figures since all we did was multiply and divide, so...

7.58 moles ${O}_{2}$