In the equation #2KClO_3 -> 2KCI + 3O_2#, how many moles of oxygen are produced when 5.05 m of #KClO_3# decompose completely?

1 Answer
Nov 18, 2016

Answer:

7.58 moles of #O_2# are produced.

Explanation:

There are multiple lines of reasoning for solving this. Let me give you the most detailed:

You start with a plan: we will convert moles of #KClO_3# to moles of #O_2# using the balanced chemical equation:

You will get 3 moles of #O_2# for every 2 moles of #KClO_3# you decompose.

Now let's substitute the number of moles of #KClO_3# that you actually started with:

#5.05 " moles "KClO_3 xx (3 " moles " O_2)/(2 " moles " KClO_3) = 7.575 " moles " O_2#

Finally, since we started with three significant figures, we have to end up with three significant figures since all we did was multiply and divide, so...

7.58 moles #O_2#