Question

In the equation: `"_90^234Th ->` `"_91^234Pa + X`, which particle is represented by X?

Answer 1

The particle is an electron `=""_-1^0e`

Explanation:

`""_90^234Th->""_91^234Pa+X`

We have conservation of the number of nucleons and charge number

For `X`, the number of nucleons is `=0` and the charge number is `=-1`

`""_-1^0 X`

This particle is `beta^-` which is an electron `""_-1^0e`