Question

In the equation, `I_2 + O_2 -> I_4O_9` what should be the coefficients of the reactants and products?

Answer 1

`4I_2 + 9O_2 -> 2I_4O_9`

Explanation:

We require a multiple of `9` times the `O_2` in order to get a multiple of `O_9` on the right hand side.

Then `9O_2` contains `2xx9` oxygen atoms, so we need a multiplier `2` on the right hand side.

Then the right hand side has `8` iodine atoms, so we need a multiplier of `4` on the `I_2` on the left hand side.