In the ideal gas law, what would you use for R when P is in Pascals?

1 Answer
anor277
Oct 26, 2015

Explanation:

Values (and importantly!) units will be included as supplementary material in any exam you will ever sit. For chemists, #R = 0.0821 *L*atm*K^-1 *mol^-1#, the value is usually most useful in that both litres and atmospheres are handy units (more so than #m^3# and Pascals).

When pressure is measured in Pascals, #R = 8.314*m^3*Pa*K^-1mol^-1#. Note here that volume is measured in #m^3#; #1# #m^3# #=# #1000# #L#.

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