In the ideal gas law, what would you use for R when P is in Pascals?

1 Answer
Oct 26, 2015

Explanation:

Values (and importantly!) units will be included as supplementary material in any exam you will ever sit. For chemists, R = 0.0821 *L*atm*K^-1 *mol^-1, the value is usually most useful in that both litres and atmospheres are handy units (more so than m^3 and Pascals).

When pressure is measured in Pascals, R = 8.314*m^3*Pa*K^-1mol^-1. Note here that volume is measured in m^3; 1 m^3 = 1000 L.