# In the morning, a concrete statue of specific heat = 600 j/(kg k) has a temperature of 15°c. during the day, it sits in the sun and warms up to 40°c, gaining 90,000 j of thermal energy. what is its mass?

Jun 17, 2014

6.0 kg

The equation we need to use is: ∆Q=mc∆θ

The following data is given:
∆Q=90000J
$c = 600 J k {g}^{-} 1 {K}^{-} 1$
∆θ=40-15=25 ºC

Note that it is not necessary to convert the temperatures into Kelvin as the temperature difference is the same ($313 - 288 = 25 K$).

Rearrange for mass and sub. in values:
m=(∆Q)/(c∆θ)=90000/(600×25)=6.0kg